Template:MT book:C1:full proofs:Proposition1.1.1: Revision history

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7 November 2007

  • curprev 07:4307:43, 7 November 2007 imported>Bunder 561 bytes +561 New page: <math>(\Rightarrow)</math> Property 1, it's direct. For property 2 , note that <math>\forall A \in \mathcal{A} </math>: :<math> A^c = X \setminus A \in \mathcal{A} </math> Finally for ...