Calculus/Integration/Solutions

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Solutions to Set One

Solutions to Set Two

  1. 113x13+C
  2. 2x4+C
  3. 43x3+114x4+C
  4. 3133x33+x495x5+C
  5. 5x1+C

Solutions to Set Three

1. (cosx+sinx)dx

=cosxdx+sinxdx
=sinxcosx +C

2. 3sinxdx

=3×sinxdx
=3cosx+C 

3. 1+tan2xdx

=sec2xdx
=tanx+C

4. 3x2/2tanx+C

5. ex+ C

6. 8ex+ C

7. 17ln|7x|+ C

8. with the substitution x=atanθ, we have dx=asec2θdθ, and x2+a2=a2sec2θ, so that

1x2+a2dx
=asec2θdθa2sec2θ
=1adθ
=1aθ+C
=1aarctanxa+C